1/(2x)=x^2

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Solution for 1/(2x)=x^2 equation: 



1/(2x)=x^2

We move all terms to the left:

1/(2x)-(x^2)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



determiningTheFunctionDomain
-x^2+1/2x=0

We add all the numbers together, and all the variables

-1x^2+1/2x=0

We multiply all the terms by the denominator


-1x^2*2x+1=0

Wy multiply elements

-2x^3+1=0

We do not support expression: x^3

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